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Total Accepted: 221656
Total Submissions: 571422
Difficulty: Easy
Contributor: LeetCode

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.

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(H) Merge k Sorted Lists (E) Merge Sorted Array (M) Sort List (M) Shortest Word Distance II

** 解题思路**
recursive 递归解法。 类似merge two sorted array

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ListNode mergeTwoLists(ListNode l1, ListNode l2) {
      // use recursive 
      if (l2 == null)  return l1;
      if (l1 == null)  return l2;
      
      ListNode mergeHead;
      
      if (l1.val < l2.val) {
          mergeHead = l1;
          mergeHead.next = mergeTwoLists(l1.next, l2);
      } else {
          mergeHead = l2;
          mergeHead.next = mergeTwoLists(l1, l2.next);
      }
      return mergeHead;
    }
    
    public ListNode mergeTwoListsFailed(ListNode l1, ListNode l2) {
        ListNode p1 = l1;
        ListNode p2 = l2 ;
        ListNode p = new ListNode(0);
        
        
        while (p1 != null && p2 != null) {
            // p.next = (p1.val > p2.val) ? new ListNode(p1.val) : new ListNode(p2.val);
            if (p1.val > p2.val) {
                p.next = new ListNode(p1.val);
                p1 = p1.next;
            } else {
                p.next = new ListNode(p2.val);
                p2 = p2.next;
            }
         
        }
        
        while (p2 != null) {
          p.next = new ListNode(p2.val);
          p2 = p2.next;
         
        }
        
        while (p1 != null) {
            p.next = new ListNode(p1.val);
            p1 = p1.next;
          
        }
        return p;
    }
}